X^2-51x+50=0

Solution for X^2-51x+50=0 equation:

X^2-51X+50=0

a = 1; b = -51; c = +50;
Δ = b2-4ac
Δ = -512-4·1·50
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-49}{2*1}=\frac{2}{2}
=1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+49}{2*1}=\frac{100}{2}
=50
$